Search a number
-
+
55253420143 = 193286287151
BaseRepresentation
bin110011011101010111…
…000100100001101111
312021121201001120021021
4303131113010201233
51401124333421033
641214424315011
73664142215315
oct633527044157
9167551046237
1055253420143
112148412a399
12a860312a67
13529726a95c
14296231c0b5
151685ba8b2d
hexcdd5c486f

55253420143 has 4 divisors (see below), whose sum is σ = 55539707488. Its totient is φ = 54967132800.

The previous prime is 55253420093. The next prime is 55253420147. The reversal of 55253420143 is 34102435255.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55253420143 - 217 = 55253289071 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55253420099 and 55253420108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55253420147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143143383 + ... + 143143768.

It is an arithmetic number, because the mean of its divisors is an integer number (13884926872).

Almost surely, 255253420143 is an apocalyptic number.

55253420143 is a deficient number, since it is larger than the sum of its proper divisors (286287345).

55253420143 is a wasteful number, since it uses less digits than its factorization.

55253420143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 286287344.

The product of its (nonzero) digits is 72000, while the sum is 34.

Adding to 55253420143 its reverse (34102435255), we get a palindrome (89355855398).

The spelling of 55253420143 in words is "fifty-five billion, two hundred fifty-three million, four hundred twenty thousand, one hundred forty-three".

Divisors: 1 193 286287151 55253420143