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55276241677 is a prime number
BaseRepresentation
bin110011011110101110…
…001000001100001101
312021200022000000112021
4303132232020030031
51401201204213202
641221001410141
73664540205356
oct633656101415
9167608000467
1055276241677
1121495aa7568
12a867a99951
13529bbcb417
14296537cd2d
151687bb5a37
hexcdeb8830d

55276241677 has 2 divisors, whose sum is σ = 55276241678. Its totient is φ = 55276241676.

The previous prime is 55276241543. The next prime is 55276241681. The reversal of 55276241677 is 77614267255.

55276241677 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37398144996 + 17878096681 = 193386^2 + 133709^2 .

It is a cyclic number.

It is not a de Polignac number, because 55276241677 - 215 = 55276208909 is a prime.

It is a super-3 number, since 3×552762416773 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55276241687) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27638120838 + 27638120839.

It is an arithmetic number, because the mean of its divisors is an integer number (27638120839).

Almost surely, 255276241677 is an apocalyptic number.

It is an amenable number.

55276241677 is a deficient number, since it is larger than the sum of its proper divisors (1).

55276241677 is an equidigital number, since it uses as much as digits as its factorization.

55276241677 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4939200, while the sum is 52.

The spelling of 55276241677 in words is "fifty-five billion, two hundred seventy-six million, two hundred forty-one thousand, six hundred seventy-seven".