Base | Representation |
---|---|
bin | 111110110111101100011111… |
… | …0001011111000010011101111 |
3 | 2200112001110202221120121001111 |
4 | 1331233120332023320103233 |
5 | 1034441023440223244413 |
6 | 5240054224150252451 |
7 | 224324554565453536 |
oct | 17557307613702357 |
9 | 2615043687517044 |
10 | 553012442399983 |
11 | 150230294803925 |
12 | 52035624057127 |
13 | 1a975b076169c7 |
14 | 9a7bd3321931d |
15 | 43e01c92add3d |
hex | 1f6f63e2f84ef |
553012442399983 has 2 divisors, whose sum is σ = 553012442399984. Its totient is φ = 553012442399982.
The previous prime is 553012442399957. The next prime is 553012442399987. The reversal of 553012442399983 is 389993244210355.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-553012442399983 is a prime.
It is a super-2 number, since 2×5530124423999832 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (553012442399987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276506221199991 + 276506221199992.
It is an arithmetic number, because the mean of its divisors is an integer number (276506221199992).
Almost surely, 2553012442399983 is an apocalyptic number.
553012442399983 is a deficient number, since it is larger than the sum of its proper divisors (1).
553012442399983 is an equidigital number, since it uses as much as digits as its factorization.
553012442399983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 251942400, while the sum is 67.
The spelling of 553012442399983 in words is "five hundred fifty-three trillion, twelve billion, four hundred forty-two million, three hundred ninety-nine thousand, nine hundred eighty-three".
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