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55312503149 = 239323114293
BaseRepresentation
bin110011100000111000…
…011101000101101101
312021202211020021220202
4303200320131011231
51401240000100044
641224334523245
73665460343061
oct634070350555
9167684207822
1055312503149
1121504514322
12a878066525
1352a6586407
14296a0dbaa1
15168ae79c4e
hexce0e1d16d

55312503149 has 4 divisors (see below), whose sum is σ = 55335619836. Its totient is φ = 55289386464.

The previous prime is 55312503139. The next prime is 55312503157. The reversal of 55312503149 is 94130521355.

55312503149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5997418249 + 49315084900 = 77443^2 + 222070^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55312503149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55312503119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11554754 + ... + 11559539.

It is an arithmetic number, because the mean of its divisors is an integer number (13833904959).

Almost surely, 255312503149 is an apocalyptic number.

It is an amenable number.

55312503149 is a deficient number, since it is larger than the sum of its proper divisors (23116687).

55312503149 is a wasteful number, since it uses less digits than its factorization.

55312503149 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23116686.

The product of its (nonzero) digits is 81000, while the sum is 38.

The spelling of 55312503149 in words is "fifty-five billion, three hundred twelve million, five hundred three thousand, one hundred forty-nine".

Divisors: 1 2393 23114293 55312503149