Base | Representation |
---|---|
bin | 11001001001110100100000… |
… | …11001011000100111010011 |
3 | 21020211212112212110121021111 |
4 | 30210322100121120213103 |
5 | 24222222021410131121 |
6 | 313350240250434151 |
7 | 14436142662321655 |
oct | 1444722031304723 |
9 | 236755485417244 |
10 | 55313011411411 |
11 | 16696130a30916 |
12 | 6254047732957 |
13 | 24b2cc1181940 |
14 | d9324218c6d5 |
15 | 65dc41e982e1 |
hex | 324e906589d3 |
55313011411411 has 4 divisors (see below), whose sum is σ = 59567858443072. Its totient is φ = 51058164379752.
The previous prime is 55313011411397. The next prime is 55313011411477. The reversal of 55313011411411 is 11411411031355.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55313011411411 - 211 = 55313011409363 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55313011441411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2127423515811 + ... + 2127423515836.
It is an arithmetic number, because the mean of its divisors is an integer number (14891964610768).
Almost surely, 255313011411411 is an apocalyptic number.
55313011411411 is a deficient number, since it is larger than the sum of its proper divisors (4254847031661).
55313011411411 is a wasteful number, since it uses less digits than its factorization.
55313011411411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4254847031660.
The product of its (nonzero) digits is 3600, while the sum is 31.
Adding to 55313011411411 its reverse (11411411031355), we get a palindrome (66724422442766).
The spelling of 55313011411411 in words is "fifty-five trillion, three hundred thirteen billion, eleven million, four hundred eleven thousand, four hundred eleven".
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