Base | Representation |
---|---|
bin | 11001001001110100100001… |
… | …11111100000100011110111 |
3 | 21020211212120120021100111101 |
4 | 30210322100333200203313 |
5 | 24222222031434433211 |
6 | 313350241244550531 |
7 | 14436143143265026 |
oct | 1444722077404367 |
9 | 236755516240441 |
10 | 55313021405431 |
11 | 16696136637539 |
12 | 625404ab52447 |
13 | 24b2cc327086a |
14 | d932436308bd |
15 | 65dc42cbe5c1 |
hex | 324e90fe08f7 |
55313021405431 has 2 divisors, whose sum is σ = 55313021405432. Its totient is φ = 55313021405430.
The previous prime is 55313021405413. The next prime is 55313021405471. The reversal of 55313021405431 is 13450412031355.
Together with previous prime (55313021405413) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55313021405431 - 223 = 55313013016823 is a prime.
It is a super-2 number, since 2×553130214054312 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55313021405471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27656510702715 + 27656510702716.
It is an arithmetic number, because the mean of its divisors is an integer number (27656510702716).
Almost surely, 255313021405431 is an apocalyptic number.
55313021405431 is a deficient number, since it is larger than the sum of its proper divisors (1).
55313021405431 is an equidigital number, since it uses as much as digits as its factorization.
55313021405431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 37.
Adding to 55313021405431 its reverse (13450412031355), we get a palindrome (68763433436786).
The spelling of 55313021405431 in words is "fifty-five trillion, three hundred thirteen billion, twenty-one million, four hundred five thousand, four hundred thirty-one".
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