Search a number
-
+
55313021405431 is a prime number
BaseRepresentation
bin11001001001110100100001…
…11111100000100011110111
321020211212120120021100111101
430210322100333200203313
524222222031434433211
6313350241244550531
714436143143265026
oct1444722077404367
9236755516240441
1055313021405431
1116696136637539
12625404ab52447
1324b2cc327086a
14d932436308bd
1565dc42cbe5c1
hex324e90fe08f7

55313021405431 has 2 divisors, whose sum is σ = 55313021405432. Its totient is φ = 55313021405430.

The previous prime is 55313021405413. The next prime is 55313021405471. The reversal of 55313021405431 is 13450412031355.

Together with previous prime (55313021405413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 55313021405431 - 223 = 55313013016823 is a prime.

It is a super-2 number, since 2×553130214054312 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55313021405471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27656510702715 + 27656510702716.

It is an arithmetic number, because the mean of its divisors is an integer number (27656510702716).

Almost surely, 255313021405431 is an apocalyptic number.

55313021405431 is a deficient number, since it is larger than the sum of its proper divisors (1).

55313021405431 is an equidigital number, since it uses as much as digits as its factorization.

55313021405431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108000, while the sum is 37.

Adding to 55313021405431 its reverse (13450412031355), we get a palindrome (68763433436786).

The spelling of 55313021405431 in words is "fifty-five trillion, three hundred thirteen billion, twenty-one million, four hundred five thousand, four hundred thirty-one".