Base | Representation |
---|---|
bin | 11001001001110100100001… |
… | …11111100000100101101001 |
3 | 21020211212120120021100122121 |
4 | 30210322100333200211221 |
5 | 24222222031434434140 |
6 | 313350241244551241 |
7 | 14436143143265251 |
oct | 1444722077404551 |
9 | 236755516240577 |
10 | 55313021405545 |
11 | 16696136637632 |
12 | 625404ab52521 |
13 | 24b2cc3270927 |
14 | d93243630961 |
15 | 65dc42cbe64a |
hex | 324e90fe0969 |
55313021405545 has 8 divisors (see below), whose sum is σ = 66375671080320. Its totient is φ = 44250386862000.
The previous prime is 55313021405531. The next prime is 55313021405557. The reversal of 55313021405545 is 54550412031355.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 55313021405545 - 213 = 55313021397353 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7111920 + ... + 12696670.
It is an arithmetic number, because the mean of its divisors is an integer number (8296958885040).
Almost surely, 255313021405545 is an apocalyptic number.
It is an amenable number.
55313021405545 is a deficient number, since it is larger than the sum of its proper divisors (11062649674775).
55313021405545 is a wasteful number, since it uses less digits than its factorization.
55313021405545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7565615.
The product of its (nonzero) digits is 900000, while the sum is 43.
The spelling of 55313021405545 in words is "fifty-five trillion, three hundred thirteen billion, twenty-one million, four hundred five thousand, five hundred forty-five".
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