Base | Representation |
---|---|
bin | 111110111000100100001110… |
… | …1000010011001111000110001 |
3 | 2200112110220202020210121122201 |
4 | 1331301020131002121320301 |
5 | 1040000004113202232431 |
6 | 5240225222152103201 |
7 | 224336323126663540 |
oct | 17561103502317061 |
9 | 2615426666717581 |
10 | 553132145352241 |
11 | 150277030a20644 |
12 | 52054870394b01 |
13 | 1a9841a30c7c80 |
14 | 9a83a4ad1a157 |
15 | 43e338313a461 |
hex | 1f7121d099e31 |
553132145352241 has 32 divisors (see below), whose sum is σ = 710380773527040. Its totient is φ = 418612876222464.
The previous prime is 553132145352229. The next prime is 553132145352251. The reversal of 553132145352241 is 142253541231355.
It is not a de Polignac number, because 553132145352241 - 29 = 553132145351729 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 553132145352191 and 553132145352200.
It is not an unprimeable number, because it can be changed into a prime (553132145352251) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 481387555 + ... + 482535223.
It is an arithmetic number, because the mean of its divisors is an integer number (22199399172720).
Almost surely, 2553132145352241 is an apocalyptic number.
It is an amenable number.
553132145352241 is a deficient number, since it is larger than the sum of its proper divisors (157248628174799).
553132145352241 is a wasteful number, since it uses less digits than its factorization.
553132145352241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1377985.
The product of its digits is 2160000, while the sum is 46.
Adding to 553132145352241 its reverse (142253541231355), we get a palindrome (695385686583596).
The spelling of 553132145352241 in words is "five hundred fifty-three trillion, one hundred thirty-two billion, one hundred forty-five million, three hundred fifty-two thousand, two hundred forty-one".
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