Base | Representation |
---|---|
bin | 11001001001110110100110… |
… | …00100111000011010111101 |
3 | 21020211222102211111101102210 |
4 | 30210323103010320122331 |
5 | 24222231314302011031 |
6 | 313350543252211033 |
7 | 14436212465154210 |
oct | 1444732304703275 |
9 | 236758384441383 |
10 | 55314130110141 |
11 | 16696655457821 |
12 | 62542ba309a79 |
13 | 24b313bb7b656 |
14 | d9330a997777 |
15 | 65dcaa2c4746 |
hex | 324ed31386bd |
55314130110141 has 16 divisors (see below), whose sum is σ = 84659511919104. Its totient is φ = 31468831727664.
The previous prime is 55314130110103. The next prime is 55314130110193. The reversal of 55314130110141 is 14101103141355.
It is not a de Polignac number, because 55314130110141 - 211 = 55314130108093 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55314130110099 and 55314130110108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55314130110241) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5801770995 + ... + 5801780528.
It is an arithmetic number, because the mean of its divisors is an integer number (5291219494944).
Almost surely, 255314130110141 is an apocalyptic number.
It is an amenable number.
55314130110141 is a deficient number, since it is larger than the sum of its proper divisors (29345381808963).
55314130110141 is a wasteful number, since it uses less digits than its factorization.
55314130110141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11603551760.
The product of its (nonzero) digits is 3600, while the sum is 30.
Adding to 55314130110141 its reverse (14101103141355), we get a palindrome (69415233251496).
The spelling of 55314130110141 in words is "fifty-five trillion, three hundred fourteen billion, one hundred thirty million, one hundred ten thousand, one hundred forty-one".
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