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55319039441 is a prime number
BaseRepresentation
bin110011100001010001…
…011000110111010001
312021210021112101000122
4303201101120313101
51401243133230231
641225131000025
73665600035241
oct634121306721
9167707471018
1055319039441
1121508179116
12a87a299015
1352a7a34543
14296ad1db21
15168b81b77b
hexce1458dd1

55319039441 has 2 divisors, whose sum is σ = 55319039442. Its totient is φ = 55319039440.

The previous prime is 55319039423. The next prime is 55319039507. The reversal of 55319039441 is 14493091355.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42681907216 + 12637132225 = 206596^2 + 112415^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55319039441 is a prime.

It is a super-2 number, since 2×553190394412 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 55319039392 and 55319039401.

It is not a weakly prime, because it can be changed into another prime (55319039141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27659519720 + 27659519721.

It is an arithmetic number, because the mean of its divisors is an integer number (27659519721).

Almost surely, 255319039441 is an apocalyptic number.

It is an amenable number.

55319039441 is a deficient number, since it is larger than the sum of its proper divisors (1).

55319039441 is an equidigital number, since it uses as much as digits as its factorization.

55319039441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 291600, while the sum is 44.

The spelling of 55319039441 in words is "fifty-five billion, three hundred nineteen million, thirty-nine thousand, four hundred forty-one".