Base | Representation |
---|---|
bin | 110011100001101110… |
… | …110001001001100011 |
3 | 12021210211000122200221 |
4 | 303201232301021203 |
5 | 1401302121203331 |
6 | 41230004023511 |
7 | 3666022353106 |
oct | 634156611143 |
9 | 167724018627 |
10 | 55326741091 |
11 | 21511559516 |
12 | a880991b97 |
13 | 52a94ccc2b |
14 | 296bd6673d |
15 | 168c33d711 |
hex | ce1bb1263 |
55326741091 has 2 divisors, whose sum is σ = 55326741092. Its totient is φ = 55326741090.
The previous prime is 55326741089. The next prime is 55326741133. The reversal of 55326741091 is 19014762355.
55326741091 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55326741091 - 21 = 55326741089 is a prime.
It is a super-2 number, since 2×553267410912 (a number of 22 digits) contains 22 as substring.
Together with 55326741089, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (55326744091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27663370545 + 27663370546.
It is an arithmetic number, because the mean of its divisors is an integer number (27663370546).
Almost surely, 255326741091 is an apocalyptic number.
55326741091 is a deficient number, since it is larger than the sum of its proper divisors (1).
55326741091 is an equidigital number, since it uses as much as digits as its factorization.
55326741091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 226800, while the sum is 43.
The spelling of 55326741091 in words is "fifty-five billion, three hundred twenty-six million, seven hundred forty-one thousand, ninety-one".
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