Base | Representation |
---|---|
bin | 111110111001110111101100… |
… | …1101100010011110111001011 |
3 | 2200120010001110002210012022022 |
4 | 1331303233121230103313023 |
5 | 1040010423223423111410 |
6 | 5240443425553315055 |
7 | 224355300255214406 |
oct | 17563573154236713 |
9 | 2616101402705268 |
10 | 553311404113355 |
11 | 150336059906aa8 |
12 | 52083559865a8b |
13 | 1a9980702c1714 |
14 | 9a8c5b44c4d3d |
15 | 43e7d75727455 |
hex | 1f73bd9b13dcb |
553311404113355 has 8 divisors (see below), whose sum is σ = 664116875320752. Its totient is φ = 442553663034208.
The previous prime is 553311404113271. The next prime is 553311404113367.
553311404113355 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-553311404113355 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11932506557 + ... + 11932552926.
It is an arithmetic number, because the mean of its divisors is an integer number (83014609415094).
Almost surely, 2553311404113355 is an apocalyptic number.
553311404113355 is a deficient number, since it is larger than the sum of its proper divisors (110805471207397).
553311404113355 is a wasteful number, since it uses less digits than its factorization.
553311404113355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23865064125.
The product of its (nonzero) digits is 810000, while the sum is 44.
It can be divided in two parts, 55331140 and 4113355, that added together give a palindrome (59444495).
The spelling of 553311404113355 in words is "five hundred fifty-three trillion, three hundred eleven billion, four hundred four million, one hundred thirteen thousand, three hundred fifty-five".
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