Base | Representation |
---|---|
bin | 11001001010010110110000… |
… | …11101110111000010101011 |
3 | 21020220122000102121200122120 |
4 | 30211023120131313002223 |
5 | 24223022202001211410 |
6 | 313402521110522323 |
7 | 14440363453261353 |
oct | 1445133035670253 |
9 | 236818012550576 |
10 | 55331400413355 |
11 | 166a2a08057190 |
12 | 625771a0663a3 |
13 | 24b4961b72891 |
14 | d940a8519b63 |
15 | 65e46b591570 |
hex | 3252d87770ab |
55331400413355 has 128 divisors (see below), whose sum is σ = 99388925337600. Its totient is φ = 26049641103360.
The previous prime is 55331400413209. The next prime is 55331400413381.
55331400413355 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 55331400413355 - 220 = 55331399364779 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 7233804571 + ... + 7233812219.
It is an arithmetic number, because the mean of its divisors is an integer number (776475979200).
Almost surely, 255331400413355 is an apocalyptic number.
55331400413355 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55331400413355 is a deficient number, since it is larger than the sum of its proper divisors (44057524924245).
55331400413355 is a wasteful number, since it uses less digits than its factorization.
55331400413355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9941.
The product of its (nonzero) digits is 810000, while the sum is 42.
It can be divided in two parts, 55331400 and 413355, that added together give a palindrome (55744755).
The spelling of 55331400413355 in words is "fifty-five trillion, three hundred thirty-one billion, four hundred million, four hundred thirteen thousand, three hundred fifty-five".
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