Base | Representation |
---|---|
bin | 11001001010010111000011… |
… | …11111100001101010110010 |
3 | 21020220122102120100101212202 |
4 | 30211023201333201222302 |
5 | 24223023013404434100 |
6 | 313402545020223202 |
7 | 14440400433601631 |
oct | 1445134177415262 |
9 | 236818376311782 |
10 | 55331560233650 |
11 | 166a2a8a296578 |
12 | 625776369ab02 |
13 | 24b4988ccc5bc |
14 | d940c183d518 |
15 | 65e47a6107d5 |
hex | 3252e1fe1ab2 |
55331560233650 has 24 divisors (see below), whose sum is σ = 105310113713904. Its totient is φ = 21617911904400.
The previous prime is 55331560233643. The next prime is 55331560233673. The reversal of 55331560233650 is 5633206513355.
It is a junction number, because it is equal to n+sod(n) for n = 55331560233595 and 55331560233604.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12867802556 + ... + 12867806855.
It is an arithmetic number, because the mean of its divisors is an integer number (4387921404746).
Almost surely, 255331560233650 is an apocalyptic number.
55331560233650 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
55331560233650 is a deficient number, since it is larger than the sum of its proper divisors (49978553480254).
55331560233650 is a wasteful number, since it uses less digits than its factorization.
55331560233650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25735609466 (or 25735609461 counting only the distinct ones).
The product of its (nonzero) digits is 3645000, while the sum is 47.
The spelling of 55331560233650 in words is "fifty-five trillion, three hundred thirty-one billion, five hundred sixty million, two hundred thirty-three thousand, six hundred fifty".
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