Base | Representation |
---|---|
bin | 101000010000101100001… |
… | …1011101001110010010011 |
3 | 201120222200021011221001011 |
4 | 1100201120123221302103 |
5 | 1211124401242140144 |
6 | 15434002022151351 |
7 | 1110526563612211 |
oct | 120413033516223 |
9 | 21528607157034 |
10 | 5533401521299 |
11 | 184377a9a3313 |
12 | 7544b0b82557 |
13 | 311a4a213512 |
14 | 151b64a99cb1 |
15 | 98e0a8d6a34 |
hex | 508586e9c93 |
5533401521299 has 2 divisors, whose sum is σ = 5533401521300. Its totient is φ = 5533401521298.
The previous prime is 5533401521273. The next prime is 5533401521357. The reversal of 5533401521299 is 9921251043355.
5533401521299 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5533401521299 - 219 = 5533400997011 is a prime.
It is not a weakly prime, because it can be changed into another prime (5533401551299) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2766700760649 + 2766700760650.
It is an arithmetic number, because the mean of its divisors is an integer number (2766700760650).
Almost surely, 25533401521299 is an apocalyptic number.
5533401521299 is a deficient number, since it is larger than the sum of its proper divisors (1).
5533401521299 is an equidigital number, since it uses as much as digits as its factorization.
5533401521299 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458000, while the sum is 49.
The spelling of 5533401521299 in words is "five trillion, five hundred thirty-three billion, four hundred one million, five hundred twenty-one thousand, two hundred ninety-nine".
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