Base | Representation |
---|---|
bin | 1001000001011111100010… |
… | …1001001110100000011011 |
3 | 1022010110111001011202200111 |
4 | 2100113320221032200123 |
5 | 2300022210231341410 |
6 | 33033432041345151 |
7 | 2042533564302361 |
oct | 220277051164033 |
9 | 38113431152614 |
10 | 9921251043355 |
11 | 3185640627373 |
12 | 114297aa981b7 |
13 | 56c75427a162 |
14 | 2642965ad631 |
15 | 12311b6e3b8a |
hex | 905f8a4e81b |
9921251043355 has 64 divisors (see below), whose sum is σ = 12942602496000. Its totient is φ = 7277461880832.
The previous prime is 9921251043329. The next prime is 9921251043499. The reversal of 9921251043355 is 5533401521299.
It is a cyclic number.
It is not a de Polignac number, because 9921251043355 - 25 = 9921251043323 is a prime.
It is a super-3 number, since 3×99212510433553 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 9921251043299 and 9921251043308.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 156274899 + ... + 156338371.
It is an arithmetic number, because the mean of its divisors is an integer number (202228164000).
Almost surely, 29921251043355 is an apocalyptic number.
9921251043355 is a gapful number since it is divisible by the number (95) formed by its first and last digit.
9921251043355 is a deficient number, since it is larger than the sum of its proper divisors (3021351452645).
9921251043355 is a wasteful number, since it uses less digits than its factorization.
9921251043355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63988.
The product of its (nonzero) digits is 1458000, while the sum is 49.
The spelling of 9921251043355 in words is "nine trillion, nine hundred twenty-one billion, two hundred fifty-one million, forty-three thousand, three hundred fifty-five".
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