Base | Representation |
---|---|
bin | 1010010011101000… |
… | …11010100011110011 |
3 | 112021122011002121221 |
4 | 11021310122203303 |
5 | 42313030204324 |
6 | 2313024525511 |
7 | 254060333533 |
oct | 51164324363 |
9 | 15248132557 |
10 | 5533444339 |
11 | 238a5376a5 |
12 | 10a5180897 |
13 | 6a2523627 |
14 | 3a6c814c3 |
15 | 225bc90e4 |
hex | 149d1a8f3 |
5533444339 has 2 divisors, whose sum is σ = 5533444340. Its totient is φ = 5533444338.
The previous prime is 5533444333. The next prime is 5533444349. The reversal of 5533444339 is 9334443355.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5533444339 - 217 = 5533313267 is a prime.
It is a super-2 number, since 2×55334443392 = 61238012505622293842, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5533444295 and 5533444304.
It is not a weakly prime, because it can be changed into another prime (5533444333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2766722169 + 2766722170.
It is an arithmetic number, because the mean of its divisors is an integer number (2766722170).
Almost surely, 25533444339 is an apocalyptic number.
5533444339 is a deficient number, since it is larger than the sum of its proper divisors (1).
5533444339 is an equidigital number, since it uses as much as digits as its factorization.
5533444339 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1166400, while the sum is 43.
The square root of 5533444339 is about 74387.1248200924. The cubic root of 5533444339 is about 1768.7448237784.
The spelling of 5533444339 in words is "five billion, five hundred thirty-three million, four hundred forty-four thousand, three hundred thirty-nine".
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