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55341305141315 = 511068261028263
BaseRepresentation
bin11001001010101001001101…
…10101011001100001000011
321020221120120201010000002212
430211110212311121201003
524223202443104010230
6313411240011332335
714441164063132304
oct1445244665314103
9236846521100085
1055341305141315
11166a7130009976
1262596231510ab
1324b587cbb355b
14d94767b5c7ab
1565e84add0895
hex325526d59843

55341305141315 has 4 divisors (see below), whose sum is σ = 66409566169584. Its totient is φ = 44273044113048.

The previous prime is 55341305141281. The next prime is 55341305141383. The reversal of 55341305141315 is 51314150314355.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55341305141315 - 234 = 55324125272131 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5534130514127 + ... + 5534130514136.

It is an arithmetic number, because the mean of its divisors is an integer number (16602391542396).

Almost surely, 255341305141315 is an apocalyptic number.

55341305141315 is a deficient number, since it is larger than the sum of its proper divisors (11068261028269).

55341305141315 is a wasteful number, since it uses less digits than its factorization.

55341305141315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11068261028268.

The product of its (nonzero) digits is 270000, while the sum is 41.

The spelling of 55341305141315 in words is "fifty-five trillion, three hundred forty-one billion, three hundred five million, one hundred forty-one thousand, three hundred fifteen".

Divisors: 1 5 11068261028263 55341305141315