Base | Representation |
---|---|
bin | 110011100010101010… |
… | …010101001011000111 |
3 | 12021211220101221011011 |
4 | 303202222111023013 |
5 | 1401320120331033 |
6 | 41231322423051 |
7 | 3666302154115 |
oct | 634252251307 |
9 | 167756357134 |
10 | 55342355143 |
11 | 2151a353599 |
12 | a886061a87 |
13 | 52ac808c0a |
14 | 297006cab5 |
15 | 168d8c4ccd |
hex | ce2a952c7 |
55342355143 has 2 divisors, whose sum is σ = 55342355144. Its totient is φ = 55342355142.
The previous prime is 55342355093. The next prime is 55342355177. The reversal of 55342355143 is 34155324355.
55342355143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55342355143 - 213 = 55342346951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55342355096 and 55342355105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55342356143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27671177571 + 27671177572.
It is an arithmetic number, because the mean of its divisors is an integer number (27671177572).
Almost surely, 255342355143 is an apocalyptic number.
55342355143 is a deficient number, since it is larger than the sum of its proper divisors (1).
55342355143 is an equidigital number, since it uses as much as digits as its factorization.
55342355143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 540000, while the sum is 40.
Adding to 55342355143 its reverse (34155324355), we get a palindrome (89497679498).
The spelling of 55342355143 in words is "fifty-five billion, three hundred forty-two million, three hundred fifty-five thousand, one hundred forty-three".
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