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55343144030121 = 326149238225569
BaseRepresentation
bin11001001010101100101000…
…11100001100111110101001
321020221202022212022020022200
430211112110130030332221
524223220224332430441
6313412142301210413
714441260462336203
oct1445262434147651
9236852285266280
1055343144030121
11166a7994015292
126259a56b60a09
1324b5ab3b6b43c
14d948a0079773
1565e90756b7b6
hex32559470cfa9

55343144030121 has 6 divisors (see below), whose sum is σ = 79940096932410. Its totient is φ = 36895429353408.

The previous prime is 55343144030113. The next prime is 55343144030197. The reversal of 55343144030121 is 12103044134355.

55343144030121 is a `hidden beast` number, since 5 + 5 + 34 + 31 + 440 + 30 + 121 = 666.

55343144030121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 37478455461225 + 17864688568896 = 6121965^2 + 4226664^2 .

It is not a de Polignac number, because 55343144030121 - 23 = 55343144030113 is a prime.

It is a super-2 number, since 2×553431440301212 (a number of 28 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (55343144030621) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3074619112776 + ... + 3074619112793.

It is an arithmetic number, because the mean of its divisors is an integer number (13323349488735).

Almost surely, 255343144030121 is an apocalyptic number.

It is an amenable number.

55343144030121 is a deficient number, since it is larger than the sum of its proper divisors (24596952902289).

55343144030121 is a wasteful number, since it uses less digits than its factorization.

55343144030121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6149238225575 (or 6149238225572 counting only the distinct ones).

The product of its (nonzero) digits is 86400, while the sum is 36.

Adding to 55343144030121 its reverse (12103044134355), we get a palindrome (67446188164476).

The spelling of 55343144030121 in words is "fifty-five trillion, three hundred forty-three billion, one hundred forty-four million, thirty thousand, one hundred twenty-one".

Divisors: 1 3 9 6149238225569 18447714676707 55343144030121