Base | Representation |
---|---|
bin | 11001001010101100110110… |
… | …00000010001101111011111 |
3 | 21020221202121112111220112211 |
4 | 30211112123000101233133 |
5 | 24223220441030300421 |
6 | 313412201233341251 |
7 | 14441263300340554 |
oct | 1445263300215737 |
9 | 236852545456484 |
10 | 55343254150111 |
11 | 166a7a40199044 |
12 | 6259a87a07827 |
13 | 24b5b009162b5 |
14 | d948b0942a2b |
15 | 65e91206e9e1 |
hex | 32559b011bdf |
55343254150111 has 4 divisors (see below), whose sum is σ = 55456895329552. Its totient is φ = 55229612970672.
The previous prime is 55343254150103. The next prime is 55343254150127. The reversal of 55343254150111 is 11105145234355.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55343254150111 - 23 = 55343254150103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55343254150211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56820588990 + ... + 56820589963.
It is an arithmetic number, because the mean of its divisors is an integer number (13864223832388).
Almost surely, 255343254150111 is an apocalyptic number.
55343254150111 is a deficient number, since it is larger than the sum of its proper divisors (113641179441).
55343254150111 is a wasteful number, since it uses less digits than its factorization.
55343254150111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113641179440.
The product of its (nonzero) digits is 180000, while the sum is 40.
Adding to 55343254150111 its reverse (11105145234355), we get a palindrome (66448399384466).
The spelling of 55343254150111 in words is "fifty-five trillion, three hundred forty-three billion, two hundred fifty-four million, one hundred fifty thousand, one hundred eleven".
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