5535540143011 has 4 divisors (see below), whose sum is σ = 5535580209952. Its totient is φ = 5535500076072.

The previous prime is 5535540142999. The next prime is 5535540143027. The reversal of 5535540143011 is 1103410455355.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5535540143011 - 2⁷ = 5535540142883 is a prime.

It is a super-3 number, since 3×5535540143011³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5535540146011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19825515 + ... + 20102788.

It is an arithmetic number, because the mean of its divisors is an integer number (1383895052488).

Almost surely, 2^{5535540143011} is an apocalyptic number.

5535540143011 is a deficient number, since it is larger than the sum of its proper divisors (40066941).

5535540143011 is a wasteful number, since it uses less digits than its factorization.

5535540143011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40066940.

The product of its (nonzero) digits is 90000, while the sum is 37.

Adding to 5535540143011 its reverse (1103410455355), we get a palindrome (6638950598366).

The spelling of 5535540143011 in words is "five trillion, five hundred thirty-five billion, five hundred forty million, one hundred forty-three thousand, eleven".