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55357003106047 = 59938254289933
BaseRepresentation
bin11001001011000110011101…
…00000011000011011111111
321021000002002201121020102001
430211203032200120123333
524223432120243343142
6313422353421243131
714442261066465316
oct1445431640303377
9237002081536361
1055357003106047
1116702856110145
1262606844034a7
1324b71b2208496
14d9541694b27d
1565ee691145b7
hex3258ce8186ff

55357003106047 has 4 divisors (see below), whose sum is σ = 56295257396040. Its totient is φ = 54418748816056.

The previous prime is 55357003106011. The next prime is 55357003106077. The reversal of 55357003106047 is 74060130075355.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55357003106047 - 231 = 55354855622399 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55357003105988 and 55357003106006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55357003106077) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 469127144908 + ... + 469127145025.

It is an arithmetic number, because the mean of its divisors is an integer number (14073814349010).

Almost surely, 255357003106047 is an apocalyptic number.

55357003106047 is a deficient number, since it is larger than the sum of its proper divisors (938254289993).

55357003106047 is an equidigital number, since it uses as much as digits as its factorization.

55357003106047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 938254289992.

The product of its (nonzero) digits is 1323000, while the sum is 46.

The spelling of 55357003106047 in words is "fifty-five trillion, three hundred fifty-seven billion, three million, one hundred six thousand, forty-seven".

Divisors: 1 59 938254289933 55357003106047