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55368874132541 = 457121157273813
BaseRepresentation
bin11001001011011100100100…
…00100110000010000111101
321021001012202001000212100222
430211232102010300100331
524224130423234220131
6313432035402431125
714443161213525104
oct1445562204602075
9237035661025328
1055368874132541
1116707897a91042
126262a37b024a5
1324b8354723808
14d95c2139503b
156604113aa87b
hex325b9213043d

55368874132541 has 4 divisors (see below), whose sum is σ = 55490031406812. Its totient is φ = 55247716858272.

The previous prime is 55368874132513. The next prime is 55368874132549. The reversal of 55368874132541 is 14523147886355.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 32048223043225 + 23320651089316 = 5661115^2 + 4829146^2 .

It is a cyclic number.

It is not a de Polignac number, because 55368874132541 - 222 = 55368869938237 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55368874132549) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60578636450 + ... + 60578637363.

It is an arithmetic number, because the mean of its divisors is an integer number (13872507851703).

Almost surely, 255368874132541 is an apocalyptic number.

It is an amenable number.

55368874132541 is a deficient number, since it is larger than the sum of its proper divisors (121157274271).

55368874132541 is a wasteful number, since it uses less digits than its factorization.

55368874132541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121157274270.

The product of its digits is 96768000, while the sum is 62.

The spelling of 55368874132541 in words is "fifty-five trillion, three hundred sixty-eight billion, eight hundred seventy-four million, one hundred thirty-two thousand, five hundred forty-one".

Divisors: 1 457 121157273813 55368874132541