Base | Representation |
---|---|
bin | 10000000111111100010… |
… | …10011101010011010101 |
3 | 1221222000121022102112222 |
4 | 20003332022131103111 |
5 | 33034113102440323 |
6 | 1102302510352125 |
7 | 55012063013135 |
oct | 10037612352325 |
9 | 1858017272488 |
10 | 554019968213 |
11 | 1a3a5a913128 |
12 | 8b4581bb645 |
13 | 403229b0cca |
14 | 1cb597c4ac5 |
15 | e6283949c8 |
hex | 80fe29d4d5 |
554019968213 has 4 divisors (see below), whose sum is σ = 558005723520. Its totient is φ = 550034212908.
The previous prime is 554019968197. The next prime is 554019968231. The reversal of 554019968213 is 312869910455.
554019968213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 554019968213 - 24 = 554019968197 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (554019968233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1992877445 + ... + 1992877722.
It is an arithmetic number, because the mean of its divisors is an integer number (139501430880).
Almost surely, 2554019968213 is an apocalyptic number.
It is an amenable number.
554019968213 is a deficient number, since it is larger than the sum of its proper divisors (3985755307).
554019968213 is a wasteful number, since it uses less digits than its factorization.
554019968213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3985755306.
The product of its (nonzero) digits is 2332800, while the sum is 53.
The spelling of 554019968213 in words is "five hundred fifty-four billion, nineteen million, nine hundred sixty-eight thousand, two hundred thirteen".
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