Base | Representation |
---|---|
bin | 11001001100101011100000… |
… | …11110010111111001110011 |
3 | 21021012021010222200220120201 |
4 | 30212111300132113321303 |
5 | 24230324230041033430 |
6 | 313503325333020031 |
7 | 14446221452341660 |
oct | 1446256036277163 |
9 | 237167128626521 |
10 | 55411260096115 |
11 | 16723868834900 |
12 | 626b0a6a84617 |
13 | 24bc34abb8b31 |
14 | d97cc27aaa67 |
15 | 6615925948ca |
hex | 326570797e73 |
55411260096115 has 48 divisors (see below), whose sum is σ = 83530501354944. Its totient is φ = 34541479906560.
The previous prime is 55411260096107. The next prime is 55411260096139. The reversal of 55411260096115 is 51169006211455.
It is not a de Polignac number, because 55411260096115 - 23 = 55411260096107 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 468048069 + ... + 468166441.
It is an arithmetic number, because the mean of its divisors is an integer number (1740218778228).
Almost surely, 255411260096115 is an apocalyptic number.
55411260096115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55411260096115 is a deficient number, since it is larger than the sum of its proper divisors (28119241258829).
55411260096115 is a wasteful number, since it uses less digits than its factorization.
55411260096115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 228940 (or 228929 counting only the distinct ones).
The product of its (nonzero) digits is 324000, while the sum is 46.
The spelling of 55411260096115 in words is "fifty-five trillion, four hundred eleven billion, two hundred sixty million, ninety-six thousand, one hundred fifteen".
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