Base | Representation |
---|---|
bin | 100001000001110… |
… | …010000000101001 |
3 | 1102121122222000222 |
4 | 201001302000221 |
5 | 2113323140423 |
6 | 130552335425 |
7 | 16505620646 |
oct | 4101620051 |
9 | 1377588028 |
10 | 554115113 |
11 | 264868982 |
12 | 1356a4575 |
13 | 8aa51586 |
14 | 53840dcd |
15 | 339a73c8 |
hex | 21072029 |
554115113 has 4 divisors (see below), whose sum is σ = 554175888. Its totient is φ = 554054340.
The previous prime is 554115091. The next prime is 554115131. The reversal of 554115113 is 311511455.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 311511455 = 5 ⋅62302291.
It is a cyclic number.
It is not a de Polignac number, because 554115113 - 212 = 554111017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (554115143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13631 + ... + 35972.
It is an arithmetic number, because the mean of its divisors is an integer number (138543972).
Almost surely, 2554115113 is an apocalyptic number.
It is an amenable number.
554115113 is a deficient number, since it is larger than the sum of its proper divisors (60775).
554115113 is a wasteful number, since it uses less digits than its factorization.
554115113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60774.
The product of its digits is 1500, while the sum is 26.
The square root of 554115113 is about 23539.6498062312. The cubic root of 554115113 is about 821.3595891431.
Adding to 554115113 its reverse (311511455), we get a palindrome (865626568).
The spelling of 554115113 in words is "five hundred fifty-four million, one hundred fifteen thousand, one hundred thirteen".
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