Base | Representation |
---|---|
bin | 11001001100101111010101… |
… | …10111000111111001011111 |
3 | 21021012110110002100210011211 |
4 | 30212113222313013321133 |
5 | 24230342431212421021 |
6 | 313504305202325251 |
7 | 14446323364230556 |
oct | 1446275267077137 |
9 | 237173402323154 |
10 | 55413313404511 |
11 | 16724721881897 |
12 | 626b57a659827 |
13 | 24bc5b740940a |
14 | d98039380d9d |
15 | 6616629873e1 |
hex | 3265eadc7e5f |
55413313404511 has 2 divisors, whose sum is σ = 55413313404512. Its totient is φ = 55413313404510.
The previous prime is 55413313404473. The next prime is 55413313404521. The reversal of 55413313404511 is 11540431331455.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55413313404511 - 223 = 55413305015903 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55413313404521) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27706656702255 + 27706656702256.
It is an arithmetic number, because the mean of its divisors is an integer number (27706656702256).
Almost surely, 255413313404511 is an apocalyptic number.
55413313404511 is a deficient number, since it is larger than the sum of its proper divisors (1).
55413313404511 is an equidigital number, since it uses as much as digits as its factorization.
55413313404511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216000, while the sum is 40.
Adding to 55413313404511 its reverse (11540431331455), we get a palindrome (66953744735966).
The spelling of 55413313404511 in words is "fifty-five trillion, four hundred thirteen billion, three hundred thirteen million, four hundred four thousand, five hundred eleven".
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