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554141131 is a prime number
BaseRepresentation
bin100001000001111…
…000010111001011
31102121201021201121
4201001320113023
52113330004011
6130553100111
716506056545
oct4101702713
91377637647
10554141131
11264886485
121356b7637
138aa6037b
145384a695
15339aee71
hex210785cb

554141131 has 2 divisors, whose sum is σ = 554141132. Its totient is φ = 554141130.

The previous prime is 554141113. The next prime is 554141167. The reversal of 554141131 is 131141455.

Together with previous prime (554141113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-554141131 is a prime.

It is a super-2 number, since 2×5541411312 = 614144786131918322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 554141096 and 554141105.

It is not a weakly prime, because it can be changed into another prime (554141101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277070565 + 277070566.

It is an arithmetic number, because the mean of its divisors is an integer number (277070566).

Almost surely, 2554141131 is an apocalyptic number.

554141131 is a deficient number, since it is larger than the sum of its proper divisors (1).

554141131 is an equidigital number, since it uses as much as digits as its factorization.

554141131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1200, while the sum is 25.

The square root of 554141131 is about 23540.2024417803. The cubic root of 554141131 is about 821.3724443537.

Adding to 554141131 its reverse (131141455), we get a palindrome (685282586).

The spelling of 554141131 in words is "five hundred fifty-four million, one hundred forty-one thousand, one hundred thirty-one".