Base | Representation |
---|---|
bin | 111110111111111010101101… |
… | …0101011000111011000111111 |
3 | 2200200001111122101012111011022 |
4 | 1331333311122223013120333 |
5 | 1040113032313131432434 |
6 | 5242321314301014355 |
7 | 224502321440110325 |
oct | 17577653253073077 |
9 | 2620044571174138 |
10 | 554142496749119 |
11 | 150626570a4a193 |
12 | 52198640b543bb |
13 | 1aa2854ab05c05 |
14 | 9aba8d6037d15 |
15 | 440e7b852222e |
hex | 1f7fd5aac763f |
554142496749119 has 2 divisors, whose sum is σ = 554142496749120. Its totient is φ = 554142496749118.
The previous prime is 554142496749071. The next prime is 554142496749181. The reversal of 554142496749119 is 911947694241455.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 554142496749119 - 236 = 554073777272383 is a prime.
It is a super-2 number, since 2×5541424967491192 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (554142496749319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277071248374559 + 277071248374560.
It is an arithmetic number, because the mean of its divisors is an integer number (277071248374560).
Almost surely, 2554142496749119 is an apocalyptic number.
554142496749119 is a deficient number, since it is larger than the sum of its proper divisors (1).
554142496749119 is an equidigital number, since it uses as much as digits as its factorization.
554142496749119 is an evil number, because the sum of its binary digits is even.
The product of its digits is 391910400, while the sum is 71.
The spelling of 554142496749119 in words is "five hundred fifty-four trillion, one hundred forty-two billion, four hundred ninety-six million, seven hundred forty-nine thousand, one hundred nineteen".
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