5541433 has 2 divisors, whose sum is σ = 5541434. Its totient is φ = 5541432.

The previous prime is 5541427. The next prime is 5541443. The reversal of 5541433 is 3341455.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2812329 + 2729104 = 1677^2 + 1652^2 .

It is a cyclic number.

It is not a de Polignac number, because 5541433 - 2⁹ = 5540921 is a prime.

It is equal to p₃₈₃₄₅₂ and since 5541433 and 383452 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 5541398 and 5541407.

It is not a weakly prime, because it can be changed into another prime (5541443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2770716 + 2770717.

It is an arithmetic number, because the mean of its divisors is an integer number (2770717).

Almost surely, 2^5541433 is an apocalyptic number.

It is an amenable number.

5541433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5541433 is an equidigital number, since it uses as much as digits as its factorization.

5541433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3600, while the sum is 25.

The square root of 5541433 is about 2354.0248511857. The cubic root of 5541433 is about 176.9595596376.

Adding to 5541433 its reverse (3341455), we get a palindrome (8882888).

The spelling of 5541433 in words is "five million, five hundred forty-one thousand, four hundred thirty-three".