Base | Representation |
---|---|
bin | 11001001100110011000110… |
… | …10111101101000000011001 |
3 | 21021012122122222202012022212 |
4 | 30212121203113231000121 |
5 | 24230411101303223113 |
6 | 313505241544524505 |
7 | 14446424444264330 |
oct | 1446314327550031 |
9 | 237178588665285 |
10 | 55415335211033 |
11 | 1672556a062a76 |
12 | 626ba43780735 |
13 | 24bc84a24a235 |
14 | d9818bab4d17 |
15 | 6617302060a8 |
hex | 3266635ed019 |
55415335211033 has 8 divisors (see below), whose sum is σ = 67057212356352. Its totient is φ = 44704808237376.
The previous prime is 55415335211023. The next prime is 55415335211081. The reversal of 55415335211033 is 33011253351455.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 55415335211033 - 28 = 55415335210777 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55415335211023) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 232837542785 + ... + 232837543022.
It is an arithmetic number, because the mean of its divisors is an integer number (8382151544544).
Almost surely, 255415335211033 is an apocalyptic number.
It is an amenable number.
55415335211033 is a deficient number, since it is larger than the sum of its proper divisors (11641877145319).
55415335211033 is a wasteful number, since it uses less digits than its factorization.
55415335211033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 465675085831.
The product of its (nonzero) digits is 405000, while the sum is 41.
Adding to 55415335211033 its reverse (33011253351455), we get a palindrome (88426588562488).
The spelling of 55415335211033 in words is "fifty-five trillion, four hundred fifteen billion, three hundred thirty-five million, two hundred eleven thousand, thirty-three".
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