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55421013003457 is a prime number
BaseRepresentation
bin11001001100111101101011…
…10010110000110011000001
321021020012022200111221022011
430212132311302300303001
524231004213312102312
6313512021211412521
714450015236601113
oct1446366562606301
9237205280457264
1055421013003457
1116727a13021502
126270b69154141
1324c024364101a
14d98569bad3b3
156619638e4da7
hex3267b5cb0cc1

55421013003457 has 2 divisors, whose sum is σ = 55421013003458. Its totient is φ = 55421013003456.

The previous prime is 55421013003451. The next prime is 55421013003481. The reversal of 55421013003457 is 75430031012455.

55421013003457 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39592900859521 + 15828112143936 = 6292289^2 + 3978456^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55421013003457 is a prime.

It is not a weakly prime, because it can be changed into another prime (55421013003451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27710506501728 + 27710506501729.

It is an arithmetic number, because the mean of its divisors is an integer number (27710506501729).

Almost surely, 255421013003457 is an apocalyptic number.

It is an amenable number.

55421013003457 is a deficient number, since it is larger than the sum of its proper divisors (1).

55421013003457 is an equidigital number, since it uses as much as digits as its factorization.

55421013003457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252000, while the sum is 40.

The spelling of 55421013003457 in words is "fifty-five trillion, four hundred twenty-one billion, thirteen million, three thousand, four hundred fifty-seven".