Base | Representation |
---|---|
bin | 11001001100111101101011… |
… | …10010110000110011110111 |
3 | 21021020012022200111221101011 |
4 | 30212132311302300303313 |
5 | 24231004213312103021 |
6 | 313512021211413051 |
7 | 14450015236601221 |
oct | 1446366562606367 |
9 | 237205280457334 |
10 | 55421013003511 |
11 | 16727a13021551 |
12 | 6270b69154187 |
13 | 24c024364105c |
14 | d98569bad411 |
15 | 6619638e4de1 |
hex | 3267b5cb0cf7 |
55421013003511 has 2 divisors, whose sum is σ = 55421013003512. Its totient is φ = 55421013003510.
The previous prime is 55421013003487. The next prime is 55421013003563. The reversal of 55421013003511 is 11530031012455.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55421013003511 - 27 = 55421013003383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55421013003011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27710506501755 + 27710506501756.
It is an arithmetic number, because the mean of its divisors is an integer number (27710506501756).
Almost surely, 255421013003511 is an apocalyptic number.
55421013003511 is a deficient number, since it is larger than the sum of its proper divisors (1).
55421013003511 is an equidigital number, since it uses as much as digits as its factorization.
55421013003511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 55421013003511 its reverse (11530031012455), we get a palindrome (66951044015966).
The spelling of 55421013003511 in words is "fifty-five trillion, four hundred twenty-one billion, thirteen million, three thousand, five hundred eleven".
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