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55430357100127 = 144473836807441
BaseRepresentation
bin11001001101001111000101…
…01111101010011001011111
321021021002102220002020012121
430212213202233222121133
524231132332404201002
6313520204324043411
714450465631241342
oct1446474257523137
9237232386066177
1055430357100127
1116730978575649
126272936533567
1324c10a248b4c9
14d98bb4b96459
15661d0dde1237
hex3269e2bea65f

55430357100127 has 4 divisors (see below), whose sum is σ = 55434193922016. Its totient is φ = 55426520278240.

The previous prime is 55430357100121. The next prime is 55430357100161. The reversal of 55430357100127 is 72100175303455.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55430357100127 - 227 = 55430222882399 is a prime.

It is a super-3 number, since 3×554303571001273 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55430357100121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1918389274 + ... + 1918418167.

It is an arithmetic number, because the mean of its divisors is an integer number (13858548480504).

Almost surely, 255430357100127 is an apocalyptic number.

55430357100127 is a deficient number, since it is larger than the sum of its proper divisors (3836821889).

55430357100127 is a wasteful number, since it uses less digits than its factorization.

55430357100127 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3836821888.

The product of its (nonzero) digits is 441000, while the sum is 43.

The spelling of 55430357100127 in words is "fifty-five trillion, four hundred thirty billion, three hundred fifty-seven million, one hundred thousand, one hundred twenty-seven".

Divisors: 1 14447 3836807441 55430357100127