5543053433 has 4 divisors (see below), whose sum is σ = 5543212368. Its totient is φ = 5542894500.

The previous prime is 5543053427. The next prime is 5543053493. The reversal of 5543053433 is 3343503455.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3343503455 = 5 ⋅668700691.

It is a cyclic number.

It is not a de Polignac number, because 5543053433 - 2¹⁰ = 5543052409 is a prime.

It is a super-2 number, since 2×5543053433² = 61450882722186170978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5543053393 and 5543053402.

It is not an unprimeable number, because it can be changed into a prime (5543053423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1943 + ... + 105308.

It is an arithmetic number, because the mean of its divisors is an integer number (1385803092).

Almost surely, 2^5543053433 is an apocalyptic number.

It is an amenable number.

5543053433 is a deficient number, since it is larger than the sum of its proper divisors (158935).

5543053433 is a wasteful number, since it uses less digits than its factorization.

5543053433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 158934.

The product of its (nonzero) digits is 162000, while the sum is 35.

The square root of 5543053433 is about 74451.6852260578. The cubic root of 5543053433 is about 1769.7680687091.

Adding to 5543053433 its reverse (3343503455), we get a palindrome (8886556888).

The spelling of 5543053433 in words is "five billion, five hundred forty-three million, fifty-three thousand, four hundred thirty-three".