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554312114341 is a prime number
BaseRepresentation
bin10000001000011111001…
…00111010000010100101
31221222202222000222200221
420010033210322002211
533040212400124331
61102351504204341
755022241142126
oct10041744720245
91858688028627
10554312114341
111a409a812907
128b51a0096b1
134036b38c03b
141cb8651204d
15e643d51711
hex810f93a0a5

554312114341 has 2 divisors, whose sum is σ = 554312114342. Its totient is φ = 554312114340.

The previous prime is 554312114309. The next prime is 554312114413. The reversal of 554312114341 is 143411213455.

Together with next prime (554312114413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 379967452225 + 174344662116 = 616415^2 + 417546^2 .

It is a cyclic number.

It is not a de Polignac number, because 554312114341 - 25 = 554312114309 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 554312114297 and 554312114306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (554312114441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277156057170 + 277156057171.

It is an arithmetic number, because the mean of its divisors is an integer number (277156057171).

Almost surely, 2554312114341 is an apocalyptic number.

It is an amenable number.

554312114341 is a deficient number, since it is larger than the sum of its proper divisors (1).

554312114341 is an equidigital number, since it uses as much as digits as its factorization.

554312114341 is an evil number, because the sum of its binary digits is even.

The product of its digits is 28800, while the sum is 34.

Adding to 554312114341 its reverse (143411213455), we get a palindrome (697723327796).

The spelling of 554312114341 in words is "five hundred fifty-four billion, three hundred twelve million, one hundred fourteen thousand, three hundred forty-one".