Search a number
-
+
55431320433 = 371599434459
BaseRepresentation
bin110011100111111101…
…101101001101110001
312022002002210211120220
4303213331231031301
51402010404223213
641244221323253
74001432310126
oct634775551561
9168062724526
1055431320433
1121565598525
12a8aba06529
1352c5087bb8
14297bbca74d
1516965e9e23
hexce7f6d371

55431320433 has 16 divisors (see below), whose sum is σ = 75074688000. Its totient is φ = 36372823760.

The previous prime is 55431320401. The next prime is 55431320471. The reversal of 55431320433 is 33402313455.

It is a cyclic number.

It is not a de Polignac number, because 55431320433 - 25 = 55431320401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 55431320394 and 55431320403.

It is not an unprimeable number, because it can be changed into a prime (55431320533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 89643 + ... + 344816.

It is an arithmetic number, because the mean of its divisors is an integer number (4692168000).

Almost surely, 255431320433 is an apocalyptic number.

It is an amenable number.

55431320433 is a deficient number, since it is larger than the sum of its proper divisors (19643367567).

55431320433 is a wasteful number, since it uses less digits than its factorization.

55431320433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 435132.

The product of its (nonzero) digits is 64800, while the sum is 33.

Adding to 55431320433 its reverse (33402313455), we get a palindrome (88833633888).

The spelling of 55431320433 in words is "fifty-five billion, four hundred thirty-one million, three hundred twenty thousand, four hundred thirty-three".

Divisors: 1 3 71 213 599 1797 42529 127587 434459 1303377 30846589 92539767 260240941 780722823 18477106811 55431320433