Base | Representation |
---|---|
bin | 110011100111111101… |
… | …101101001101110001 |
3 | 12022002002210211120220 |
4 | 303213331231031301 |
5 | 1402010404223213 |
6 | 41244221323253 |
7 | 4001432310126 |
oct | 634775551561 |
9 | 168062724526 |
10 | 55431320433 |
11 | 21565598525 |
12 | a8aba06529 |
13 | 52c5087bb8 |
14 | 297bbca74d |
15 | 16965e9e23 |
hex | ce7f6d371 |
55431320433 has 16 divisors (see below), whose sum is σ = 75074688000. Its totient is φ = 36372823760.
The previous prime is 55431320401. The next prime is 55431320471. The reversal of 55431320433 is 33402313455.
It is a cyclic number.
It is not a de Polignac number, because 55431320433 - 25 = 55431320401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55431320394 and 55431320403.
It is not an unprimeable number, because it can be changed into a prime (55431320533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 89643 + ... + 344816.
It is an arithmetic number, because the mean of its divisors is an integer number (4692168000).
Almost surely, 255431320433 is an apocalyptic number.
It is an amenable number.
55431320433 is a deficient number, since it is larger than the sum of its proper divisors (19643367567).
55431320433 is a wasteful number, since it uses less digits than its factorization.
55431320433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 435132.
The product of its (nonzero) digits is 64800, while the sum is 33.
Adding to 55431320433 its reverse (33402313455), we get a palindrome (88833633888).
The spelling of 55431320433 in words is "fifty-five billion, four hundred thirty-one million, three hundred twenty thousand, four hundred thirty-three".
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