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55435417117 is a prime number
BaseRepresentation
bin110011101000001101…
…010101011000011101
312022002101111222011221
4303220031111120131
51402012431321432
641244445213341
74001512161613
oct635015253035
9168071458157
1055435417117
1121567936413
12a8b1261251
1352c5b90782
14297c5756b3
151696b58b97
hexce835561d

55435417117 has 2 divisors, whose sum is σ = 55435417118. Its totient is φ = 55435417116.

The previous prime is 55435417067. The next prime is 55435417157. The reversal of 55435417117 is 71171453455.

55435417117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 54821071321 + 614345796 = 234139^2 + 24786^2 .

It is a cyclic number.

It is not a de Polignac number, because 55435417117 - 231 = 53287933469 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55435417157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27717708558 + 27717708559.

It is an arithmetic number, because the mean of its divisors is an integer number (27717708559).

Almost surely, 255435417117 is an apocalyptic number.

It is an amenable number.

55435417117 is a deficient number, since it is larger than the sum of its proper divisors (1).

55435417117 is an equidigital number, since it uses as much as digits as its factorization.

55435417117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 294000, while the sum is 43.

The spelling of 55435417117 in words is "fifty-five billion, four hundred thirty-five million, four hundred seventeen thousand, one hundred seventeen".