Base | Representation |
---|---|
bin | 1010010100110111… |
… | …00101010110000011 |
3 | 112022100110202101112 |
4 | 11022123211112003 |
5 | 42323142242011 |
6 | 2314032553535 |
7 | 254243530016 |
oct | 51233452603 |
9 | 15270422345 |
10 | 5543712131 |
11 | 239530aa81 |
12 | 10a86b28ab |
13 | 6a46aa049 |
14 | 3a839537d |
15 | 226a5658b |
hex | 14a6e5583 |
5543712131 has 4 divisors (see below), whose sum is σ = 5678924664. Its totient is φ = 5408499600.
The previous prime is 5543712107. The next prime is 5543712133. The reversal of 5543712131 is 1312173455.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1312173455 = 5 ⋅262434691.
It is a cyclic number.
It is not a de Polignac number, because 5543712131 - 214 = 5543695747 is a prime.
It is a super-2 number, since 2×55437121312 = 61465488382793122322, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5543712133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67606205 + ... + 67606286.
It is an arithmetic number, because the mean of its divisors is an integer number (1419731166).
Almost surely, 25543712131 is an apocalyptic number.
5543712131 is a deficient number, since it is larger than the sum of its proper divisors (135212533).
5543712131 is a wasteful number, since it uses less digits than its factorization.
5543712131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 135212532.
The product of its digits is 12600, while the sum is 32.
The square root of 5543712131 is about 74456.1087554272. The cubic root of 5543712131 is about 1769.8381682507.
Adding to 5543712131 its reverse (1312173455), we get a palindrome (6855885586).
The spelling of 5543712131 in words is "five billion, five hundred forty-three million, seven hundred twelve thousand, one hundred thirty-one".
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