Base | Representation |
---|---|
bin | 11001001101011111111011… |
… | …00011001011110000001101 |
3 | 21021021221202212202221021211 |
4 | 30212233331203023300031 |
5 | 24231304341031421201 |
6 | 313524301323054421 |
7 | 14451235635053626 |
oct | 1446577543136015 |
9 | 237257685687254 |
10 | 55439396748301 |
11 | 16734797187065 |
12 | 6274639971411 |
13 | 24c1bb3211157 |
14 | d993d156ca4d |
15 | 66218c800651 |
hex | 326bfd8cbc0d |
55439396748301 has 2 divisors, whose sum is σ = 55439396748302. Its totient is φ = 55439396748300.
The previous prime is 55439396748287. The next prime is 55439396748317. The reversal of 55439396748301 is 10384769393455.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 35394479854276 + 20044916894025 = 5949326^2 + 4477155^2 .
It is a cyclic number.
It is not a de Polignac number, because 55439396748301 - 29 = 55439396747789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55439396743301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27719698374150 + 27719698374151.
It is an arithmetic number, because the mean of its divisors is an integer number (27719698374151).
Almost surely, 255439396748301 is an apocalyptic number.
It is an amenable number.
55439396748301 is a deficient number, since it is larger than the sum of its proper divisors (1).
55439396748301 is an equidigital number, since it uses as much as digits as its factorization.
55439396748301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 293932800, while the sum is 67.
The spelling of 55439396748301 in words is "fifty-five trillion, four hundred thirty-nine billion, three hundred ninety-six million, seven hundred forty-eight thousand, three hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •