Base | Representation |
---|---|
bin | 101000010101110001011… |
… | …0101001101000111111011 |
3 | 201122000211201211022100201 |
4 | 1100223202311031013323 |
5 | 1211314223213110133 |
6 | 15443004501543031 |
7 | 1111364153260012 |
oct | 120534265150773 |
9 | 21560751738321 |
10 | 5544313410043 |
11 | 184836a41a891 |
12 | 756637414a77 |
13 | 312a98aca815 |
14 | 1524bbd91a79 |
15 | 9934886dd7d |
hex | 50ae2d4d1fb |
5544313410043 has 8 divisors (see below), whose sum is σ = 5556155819760. Its totient is φ = 5532474726240.
The previous prime is 5544313409977. The next prime is 5544313410061. The reversal of 5544313410043 is 3400143134455.
5544313410043 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5544313410043 is a prime.
It is a super-2 number, since 2×55443134100432 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5544313409984 and 5544313410011.
It is not an unprimeable number, because it can be changed into a prime (5544313416043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2058013 + ... + 3914593.
It is an arithmetic number, because the mean of its divisors is an integer number (694519477470).
Almost surely, 25544313410043 is an apocalyptic number.
5544313410043 is a deficient number, since it is larger than the sum of its proper divisors (11842409717).
5544313410043 is a wasteful number, since it uses less digits than its factorization.
5544313410043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1862957.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 5544313410043 its reverse (3400143134455), we get a palindrome (8944456544498).
The spelling of 5544313410043 in words is "five trillion, five hundred forty-four billion, three hundred thirteen million, four hundred ten thousand, forty-three".
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