Base | Representation |
---|---|
bin | 100001000011001… |
… | …111001111101001 |
3 | 1102122101100212222 |
4 | 201003033033221 |
5 | 2113422401001 |
6 | 131004443425 |
7 | 16512101222 |
oct | 4103171751 |
9 | 1378340788 |
10 | 554497001 |
11 | 264aa9893 |
12 | 135849575 |
13 | 8ab56346 |
14 | 53900249 |
15 | 33a3061b |
hex | 210cf3e9 |
554497001 has 2 divisors, whose sum is σ = 554497002. Its totient is φ = 554497000.
The previous prime is 554496991. The next prime is 554497003. The reversal of 554497001 is 100794455.
554497001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 552250000 + 2247001 = 23500^2 + 1499^2 .
It is a cyclic number.
It is not a de Polignac number, because 554497001 - 26 = 554496937 is a prime.
Together with 554497003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (554497003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277248500 + 277248501.
It is an arithmetic number, because the mean of its divisors is an integer number (277248501).
Almost surely, 2554497001 is an apocalyptic number.
It is an amenable number.
554497001 is a deficient number, since it is larger than the sum of its proper divisors (1).
554497001 is an equidigital number, since it uses as much as digits as its factorization.
554497001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25200, while the sum is 35.
The square root of 554497001 is about 23547.7599996263. The cubic root of 554497001 is about 821.5482354687.
The spelling of 554497001 in words is "five hundred fifty-four million, four hundred ninety-seven thousand, one".
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