Base | Representation |
---|---|
bin | 11001001101110110011010… |
… | …11011000110011001001101 |
3 | 21021100002221120200022022011 |
4 | 30212323031123012121031 |
5 | 24232004104400142332 |
6 | 313534020001221221 |
7 | 14452144136653264 |
oct | 1446731533063115 |
9 | 237302846608264 |
10 | 55451474224717 |
11 | 1673992464592a |
12 | 6276a4a631811 |
13 | 24c30894314bc |
14 | d99c195975db |
15 | 662647c76e47 |
hex | 326ecd6c664d |
55451474224717 has 2 divisors, whose sum is σ = 55451474224718. Its totient is φ = 55451474224716.
The previous prime is 55451474224709. The next prime is 55451474224723. The reversal of 55451474224717 is 71742247415455.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 55359983704041 + 91490520676 = 7440429^2 + 302474^2 .
It is a cyclic number.
It is not a de Polignac number, because 55451474224717 - 23 = 55451474224709 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55451474224117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27725737112358 + 27725737112359.
It is an arithmetic number, because the mean of its divisors is an integer number (27725737112359).
Almost surely, 255451474224717 is an apocalyptic number.
It is an amenable number.
55451474224717 is a deficient number, since it is larger than the sum of its proper divisors (1).
55451474224717 is an equidigital number, since it uses as much as digits as its factorization.
55451474224717 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 43904000, while the sum is 58.
The spelling of 55451474224717 in words is "fifty-five trillion, four hundred fifty-one billion, four hundred seventy-four million, two hundred twenty-four thousand, seven hundred seventeen".
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