Base | Representation |
---|---|
bin | 101000010110010101000… |
… | …1010001100110000011101 |
3 | 201122010221010121020202011 |
4 | 1100230222022030300131 |
5 | 1211324201041032101 |
6 | 15443323331031221 |
7 | 1111435624033036 |
oct | 120545212146035 |
9 | 21563833536664 |
10 | 5545510095901 |
11 | 1848923972666 |
12 | 75691013b511 |
13 | 312c29a01669 |
14 | 152592c9ba8d |
15 | 993b8952751 |
hex | 50b2a28cc1d |
5545510095901 has 2 divisors, whose sum is σ = 5545510095902. Its totient is φ = 5545510095900.
The previous prime is 5545510095793. The next prime is 5545510095941. The reversal of 5545510095901 is 1095900155455.
5545510095901 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5415440952100 + 130069143801 = 2327110^2 + 360651^2 .
It is a cyclic number.
It is not a de Polignac number, because 5545510095901 - 213 = 5545510087709 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5545510095941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2772755047950 + 2772755047951.
It is an arithmetic number, because the mean of its divisors is an integer number (2772755047951).
Almost surely, 25545510095901 is an apocalyptic number.
It is an amenable number.
5545510095901 is a deficient number, since it is larger than the sum of its proper divisors (1).
5545510095901 is an equidigital number, since it uses as much as digits as its factorization.
5545510095901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1012500, while the sum is 49.
The spelling of 5545510095901 in words is "five trillion, five hundred forty-five billion, five hundred ten million, ninety-five thousand, nine hundred one".
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