Base | Representation |
---|---|
bin | 1101001110100… |
… | …0001111001001 |
3 | 10212101112101212 |
4 | 3103220033021 |
5 | 103200232233 |
6 | 5301022505 |
7 | 1242356042 |
oct | 323501711 |
9 | 125345355 |
10 | 55477193 |
11 | 29351922 |
12 | 166b4a35 |
13 | b655455 |
14 | 75218c9 |
15 | 4d0ca48 |
hex | 34e83c9 |
55477193 has 2 divisors, whose sum is σ = 55477194. Its totient is φ = 55477192.
The previous prime is 55477189. The next prime is 55477217. The reversal of 55477193 is 39177455.
55477193 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 55472704 + 4489 = 7448^2 + 67^2 .
It is a cyclic number.
It is not a de Polignac number, because 55477193 - 22 = 55477189 is a prime.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 55477193.
It is not a weakly prime, because it can be changed into another prime (55477133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27738596 + 27738597.
It is an arithmetic number, because the mean of its divisors is an integer number (27738597).
Almost surely, 255477193 is an apocalyptic number.
It is an amenable number.
55477193 is a deficient number, since it is larger than the sum of its proper divisors (1).
55477193 is an equidigital number, since it uses as much as digits as its factorization.
55477193 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 132300, while the sum is 41.
The square root of 55477193 is about 7448.3013499724. The cubic root of 55477193 is about 381.3919242994.
The spelling of 55477193 in words is "fifty-five million, four hundred seventy-seven thousand, one hundred ninety-three".
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