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55500504923933 is a prime number
BaseRepresentation
bin11001001111010001101111…
…11000010111111100011101
321021111210111121120220012222
430213220313320113330131
524233310013230031213
6314012325135235125
714455531152015236
oct1447506770277435
9237453447526188
1055500504923933
11167586a5152953
126284452978aa5
1324c78a1422364
14d9c34b28c08d
15663a674a1808
hex327a37e17f1d

55500504923933 has 2 divisors, whose sum is σ = 55500504923934. Its totient is φ = 55500504923932.

The previous prime is 55500504923917. The next prime is 55500504923939. The reversal of 55500504923933 is 33932940500555.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47768306977444 + 7732197946489 = 6911462^2 + 2780683^2 .

It is a cyclic number.

It is not a de Polignac number, because 55500504923933 - 24 = 55500504923917 is a prime.

It is a super-2 number, since 2×555005049239332 (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55500504923939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27750252461966 + 27750252461967.

It is an arithmetic number, because the mean of its divisors is an integer number (27750252461967).

Almost surely, 255500504923933 is an apocalyptic number.

It is an amenable number.

55500504923933 is a deficient number, since it is larger than the sum of its proper divisors (1).

55500504923933 is an equidigital number, since it uses as much as digits as its factorization.

55500504923933 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10935000, while the sum is 53.

The spelling of 55500504923933 in words is "fifty-five trillion, five hundred billion, five hundred four million, nine hundred twenty-three thousand, nine hundred thirty-three".