Base | Representation |
---|---|
bin | 110011101100010011… |
… | …000011011000010111 |
3 | 12022021011121121122202 |
4 | 303230103003120113 |
5 | 1402133012300421 |
6 | 41255335515115 |
7 | 4003304300123 |
oct | 635423033027 |
9 | 168234547582 |
10 | 55504025111 |
11 | 215a2636637 |
12 | a910228a9b |
13 | 5307162812 |
14 | 2987714583 |
15 | 169cbac10b |
hex | cec4c3617 |
55504025111 has 8 divisors (see below), whose sum is σ = 56528853648. Its totient is φ = 54482904000.
The previous prime is 55504025107. The next prime is 55504025117. The reversal of 55504025111 is 11152040555.
55504025111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 55504025111 - 22 = 55504025107 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55504025117) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 896630 + ... + 956531.
It is an arithmetic number, because the mean of its divisors is an integer number (7066106706).
Almost surely, 255504025111 is an apocalyptic number.
55504025111 is a deficient number, since it is larger than the sum of its proper divisors (1024828537).
55504025111 is a wasteful number, since it uses less digits than its factorization.
55504025111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1853713.
The product of its (nonzero) digits is 5000, while the sum is 29.
Adding to 55504025111 its reverse (11152040555), we get a palindrome (66656065666).
The spelling of 55504025111 in words is "fifty-five billion, five hundred four million, twenty-five thousand, one hundred eleven".
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