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5550505049917 is a prime number
BaseRepresentation
bin101000011000101001111…
…1000011011111100111101
3201122121211020111012112001
41100301103320123330331
51211414413243044132
615445511122142301
71112003455323142
oct120612370337475
921577736435461
105550505049917
11184aa57443533
12757884ab1991
133135447b4559
141529084083c9
15995ac20dce7
hex50c53e1bf3d

5550505049917 has 2 divisors, whose sum is σ = 5550505049918. Its totient is φ = 5550505049916.

The previous prime is 5550505049899. The next prime is 5550505049933. The reversal of 5550505049917 is 7199405050555.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5480192042361 + 70313007556 = 2340981^2 + 265166^2 .

It is a cyclic number.

It is not a de Polignac number, because 5550505049917 - 235 = 5516145311549 is a prime.

It is a super-3 number, since 3×55505050499173 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5550505049317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2775252524958 + 2775252524959.

It is an arithmetic number, because the mean of its divisors is an integer number (2775252524959).

Almost surely, 25550505049917 is an apocalyptic number.

It is an amenable number.

5550505049917 is a deficient number, since it is larger than the sum of its proper divisors (1).

5550505049917 is an equidigital number, since it uses as much as digits as its factorization.

5550505049917 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7087500, while the sum is 55.

The spelling of 5550505049917 in words is "five trillion, five hundred fifty billion, five hundred five million, forty-nine thousand, nine hundred seventeen".