Base | Representation |
---|---|
bin | 11001001111011011000011… |
… | …11100000011110101010111 |
3 | 21021112021102010001111200121 |
4 | 30213231201330003311113 |
5 | 24233400233402004003 |
6 | 314014513251052411 |
7 | 14456066112143542 |
oct | 1447554174036527 |
9 | 237467363044617 |
10 | 55505505500503 |
11 | 1675a830914063 |
12 | 62854095a1107 |
13 | 24c81ba4234c6 |
14 | d9c6a345d859 |
15 | 663c5b4bdcbd |
hex | 327b61f03d57 |
55505505500503 has 2 divisors, whose sum is σ = 55505505500504. Its totient is φ = 55505505500502.
The previous prime is 55505505500479. The next prime is 55505505500519. The reversal of 55505505500503 is 30500550550555.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55505505500503 - 233 = 55496915565911 is a prime.
It is a super-2 number, since 2×555055055005032 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 55505505500503.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55505505500563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27752752750251 + 27752752750252.
It is an arithmetic number, because the mean of its divisors is an integer number (27752752750252).
Almost surely, 255505505500503 is an apocalyptic number.
55505505500503 is a deficient number, since it is larger than the sum of its proper divisors (1).
55505505500503 is an equidigital number, since it uses as much as digits as its factorization.
55505505500503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1171875, while the sum is 43.
The spelling of 55505505500503 in words is "fifty-five trillion, five hundred five billion, five hundred five million, five hundred thousand, five hundred three".
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